PROCESSING ONE DIMENSIONAL ARRAY

TO SEARCH FOR A NUMBER IN A LIST OF NUMBERS

#include<stdio.h>

#include<conio.h>

void main()

{

int a[10},n,i,f,s;

clrscr();

printf("Enter the no of numbers
");

scanf("%d",&n);

printf("Enter %d numbers
",n);

for(i=0;i<n;i++)

scanf("%d",a[i]);

printf("Enter the number to be searched
");

scanf("%d",&s);

/* searching for s in a begins */ 

f=0;

for(i=0;i<n;i++)

if(a[i]==s)

{

f=1;

break;

}

/*searching for s in a ends*/

printf("
List of elements
");

for(i=0;i<n;i++)

printf("%d",a[i]);

printf("
Enter to be searched
");

printf("
s=%d
",s);

if(f==1)

printf("%d is found",s);

else

printf("%d is not found",s);

getch();

}

OUTPUT

Enter the no of numbers

5

Enter 5 numbers

1   2   3   4   5

Enter the number to be searched 

3

List of elements 

1   2   3   4   5

Elements to be searched

3

3 is found

Explanation

a is declared to be array of int type of size 10.Maximum 10 values can be read into the array.n,i,s and f are declared to be variable of int type.n is to collect the number of values to  be read into a, which lies within 1 and 10.i is to traverse all the elements of a.s is to collect a value which is to be searched.f is to be determine whether s is found in a or not.It acts as a flag variable.The procedure of searching for s in a is implemented in the following segment of the program.

f=0;

for(i=0;i<n;i++)

if(a[i]==s)

{

f=1;

break;

}

before searching begins,f is set to zero with the assumption that s is not available in a.During the course of searching that is inside the body of the for loop, if s is found t match with any element in the array, f is set to 1  and loop is excited. If s takes 1 then it means s  is found in a.If f retains 0,we conclude that s s not fond in a.The value of f would thus tell us whether s is found in a or not.  

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